Question

The length of the aluminium rod at temperature 303 K is 50m what would be its increase in length when it is heated to 323K(the linear coefficient of aluminium is 23×10^-6 K^-1​

Answer 1

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Answer 2

The increase in length is $4.6\times 10^{-4}\ m$ .

Given :

Length of aluminium rod is , L = 50 m .

Initial temperature , $T_i=303\ K$ .

Final temperature , $T_f=323\ K$ .

Also , linear coefficient of aluminium is , $\alpha=23\times 10^{-6}\ K^{-1}$ .

We know , expansion in length is given as :

$\Delta L=\alpha\Delta T\\\\\Delta L=23\times 10^{-6}\times ( T_f-T_i)\\\\\Delta L=23\times 10^{-6}\times 20\\\\\Delta L=0.00046\ m\\\\\Delta L=4.6\times 10^{-4}\ m$

Therefore , the increase in length is $4.6\times 10^{-4}\ m$ .

Hence , this is the required solution .

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Expansion

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