the length of the base of an isosceles triangle is 10 cm and the perimeter is 28 cm. find the length ofeach of its congruent sides
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Answered by
0
Perimeter = 28
Let the other side be X
X+X +10=28
2x=28-10
2x=18
X=9
Let the other side be X
X+X +10=28
2x=28-10
2x=18
X=9
Answered by
1
Hey!!!
________________________________
●For isosceles triangle
Let length of both congruent sides be x cm
Base=10 cm
ATQ
Perimeter=28cm
10cm+x cm+ x cm=28cm
2x=28-10
x=18/2
x=9
Hence,Length of both congruent sides are 9 cm and 9cm
________________________________
Hope it helps!!! :)
________________________________
●For isosceles triangle
Let length of both congruent sides be x cm
Base=10 cm
ATQ
Perimeter=28cm
10cm+x cm+ x cm=28cm
2x=28-10
x=18/2
x=9
Hence,Length of both congruent sides are 9 cm and 9cm
________________________________
Hope it helps!!! :)
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