the length of the diagonal of a rhombus are 16 cm and 12cm respectively.find the length of each of its sides
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We know that the diagonals of a rhombus bisect at right angles.
Let A B CD be the rhombus and AC and B D bisect at O.
A O=16/2=8 CM
BO=12/2=6 CM
In right angled △AOB
AB2=AO2+BO2
=82+62=82+62
AB2=64+36=100
AB=√100=10cm
I think this will help you.
Let A B CD be the rhombus and AC and B D bisect at O.
A O=16/2=8 CM
BO=12/2=6 CM
In right angled △AOB
AB2=AO2+BO2
=82+62=82+62
AB2=64+36=100
AB=√100=10cm
I think this will help you.
Answered by
1
Let ABCD be the rhombus, where diagonal
AC = 12cm and BD = 16cm
We know that diagonal of a rhombus bisect each other at right angles.
AO = 6cm, BO = 8cm
By Pythagoras theorm -
AB^2 = AO^2 + BO^2
AB^2 = 6^2 + 8^2
AB^2 = 36 + 64
AB^2 = 100
AB = √100
AB = 10
The length of each of it's sides is 10cm.
Mark me brainliest and thank.
AC = 12cm and BD = 16cm
We know that diagonal of a rhombus bisect each other at right angles.
AO = 6cm, BO = 8cm
By Pythagoras theorm -
AB^2 = AO^2 + BO^2
AB^2 = 6^2 + 8^2
AB^2 = 36 + 64
AB^2 = 100
AB = √100
AB = 10
The length of each of it's sides is 10cm.
Mark me brainliest and thank.
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