the length of the diagonal of a rhombus are 24 cm and 32 cm the perimeter of the Rhombus is what
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Hii friend,
Let ABCD be a rhombus and AC and BD are the Diagonals.
Length of diagonals of RHOMBUS = 24 and 32 cm.
We know that the diagonals of a rhombus bisect each other at right Angles.
Therefore,
OA= OC = 12 cm , OB = OD = 16 cm
Therefore,
By pythagoras theroem,
Side AB = ✓(OA)²+(OB)² = ✓(12)² + (16)² = ✓144 + 256 = ✓400 = 20 cm
Therefore,
Perimeter of rhombus = 4 × AB = 4 × 20 = 80 cm.
HOPE IT WILL HELP YOU..... :-)
Let ABCD be a rhombus and AC and BD are the Diagonals.
Length of diagonals of RHOMBUS = 24 and 32 cm.
We know that the diagonals of a rhombus bisect each other at right Angles.
Therefore,
OA= OC = 12 cm , OB = OD = 16 cm
Therefore,
By pythagoras theroem,
Side AB = ✓(OA)²+(OB)² = ✓(12)² + (16)² = ✓144 + 256 = ✓400 = 20 cm
Therefore,
Perimeter of rhombus = 4 × AB = 4 × 20 = 80 cm.
HOPE IT WILL HELP YOU..... :-)
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