The length of the diagonal of a square and that of the side of another square are both 10cm.what is the ratio of the area of the first square to the second
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the length of diagonal of 1st sq=10 cm
side of 1st sq=10/root2=5root2
side of 2nd square =10 cm
area of 1st square =(5root2)^2=50 sq cm
areaof 2nd square =10^2=100 sq cm
required ratio =50/100=1:2
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side of 1st sq=10/root2=5root2
side of 2nd square =10 cm
area of 1st square =(5root2)^2=50 sq cm
areaof 2nd square =10^2=100 sq cm
required ratio =50/100=1:2
Mark as brainliest
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