Question

the length of the diagonal of a square is 8sqroot2. find the length of the square and hence find its area

Answer 1

$diagonal \: of \: square = \sqrt{2 } \times side \:$
so
$side = \frac{diagonal}{ \sqrt{2} }$
$side = \frac{8 \sqrt{2} }{ \sqrt{2} }$
side =8
$area \: of \: square = {side}^{2}$


${8}^{2} = 64$
so side is 8unit
and area is 64 square units