Question

The length of the diagonals of a rhombus is 42 cm and 20 cm. Find the perimeter of the rhombus.

Answer 1

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Given :-

• Diagonal 1 = 42 cm
• Diagonal 2 = 20 cm

Using formulas,

P = 4a

$a = \sqrt{ \frac{ {p}^{2} + {q}^{2} }{2} }$

Solving for perimeter,

$p = 2 \sqrt{ {p}^{2} + {q}^{2} }$

$= > 2 \sqrt{ {42}^{2} + {20}^{2} }$

=> 93.03763 or 93.04 cm

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Answer 2

Answer:

93

Step-by-step explanation: