The length of the diagonals of a rhombus is 42 cm and 40 cm. Find the perimeter of the
rhombus.
explain it to me please help me out with this
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Answer:
Step-by-step explanation:
Diagonal AC= 20 cm, so, AO = 10 cm.
Diagonal BD= 42 cm, so, BO = 21 cm.
We know that diagonals of a rhombus bisect each other at right angles.
Here, in right angled triangle AOB
AO= 10 cm and BO = 21 cm.
By Pythagoras theorem:
AB² = AO²+BO²
=> AB² = 10²+21²
=> AB² = 100+441
=> AB² = 541
=> AB = √541
So, AB = ~23.25
Here AB is a side of the given rhombus.
Perimeter of a rhombus =
4×side
= (4×23.25) cm
= 93 cm.
Hence perimeter of the rhombus is 93 cm.
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Step-by-step explanation:
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