Math, asked by banoparveen991, 5 days ago

The length of the diagonals of a rhombus is 42 cm and 40 cm. Find the perimeter of the

rhombus.
explain it to me please help me out with this​

Attachments:

Answers

Answered by choprasiddharth10
2

Answer:

93 cm

Step-by-step explanation:

Diagonal AC= 20 cm, so, AO = 10 cm.

Diagonal BD= 42 cm, so, BO = 21 cm.

We know that diagonals of a rhombus bisect each other at right angles.

Here, in right angled triangle AOB

AO= 10 cm and BO = 21 cm.

By Pythagoras theorem:

AB² = AO²+BO²

=> AB² = 10²+21²

=> AB² = 100+441

=> AB² = 541

=> AB = √541

So, AB = ~23.25

Here AB is a side of the given rhombus.

Perimeter of a rhombus =

4×side

= (4×23.25) cm

= 93 cm.

Hence perimeter of the rhombus is 93 cm.

Answered by kashishj2005
2

Step-by-step explanation:

hope it is helpful for you.

Attachments:
Similar questions