the length of the dioganals of a rhombus are 16cm and 12cm respectively. find the length of the sides
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d 1 = 16 cm
1/2 d1 = 16/2 = 8 cm
d 2 = 12 cm
1/2 d2 = 12/2 = 6 cm
The diagonals of a rhombus bisect at right angles.
By pythagoras theorem,
hyp² = base² + alt²
hyp² = 8² + 6²
hyp² = 64 + 36
hyp = √100
hyp = 10 cm
∴ the side of the rhombus is 10 cm.
(: Hope this helpz :)
1/2 d1 = 16/2 = 8 cm
d 2 = 12 cm
1/2 d2 = 12/2 = 6 cm
The diagonals of a rhombus bisect at right angles.
By pythagoras theorem,
hyp² = base² + alt²
hyp² = 8² + 6²
hyp² = 64 + 36
hyp = √100
hyp = 10 cm
∴ the side of the rhombus is 10 cm.
(: Hope this helpz :)
nito2:
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length of two sides of rhombus is same
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