The length of the fence of a Trapezium shaped field ABCD is 130 m and side a b is perpendicular to each of the parallel sides Ad and bc. If BC =54 m, cd =19m and ad =42m, find the area of the field
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Length of AB = 54m
Length of AD = 42 m
Length of CD = 19m
Perimeter of trapezium ABCD= 130m
Length of side BC = 130-(54+42+19)
= 130-115 = 15m
Area of the trapezium field = 1/2 X h ( sum of parallel sides )
= 1/2 X AB ( AD + BC )
= 1/2 X 54 ( 42+15)
= 1/2 X 54 X 57
= 1539 m2
Length of AD = 42 m
Length of CD = 19m
Perimeter of trapezium ABCD= 130m
Length of side BC = 130-(54+42+19)
= 130-115 = 15m
Area of the trapezium field = 1/2 X h ( sum of parallel sides )
= 1/2 X AB ( AD + BC )
= 1/2 X 54 ( 42+15)
= 1/2 X 54 X 57
= 1539 m2
ehteshamul:
what is ans
1539
but ans is 720 m s
but as the question is given answer will be this only
please make again
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34
ye answer abhi complete nhi hai please aage apna aap solve kr lo
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Ok
but the ans is 720 m
i am sorry vo maine jaldi me kr diye
give my full ans
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