The length of the fence of a trapezium-shaped field ABCD is 130m and sides AD and BC.if BC=54m,cd=19m and AD=42m ,find the area of the field.
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Given_BC=54m, CD=19m and AD=42m
The perimeter of the field is 130m.
AB +BC+CD +AD=130m
AB=130-54-19-42
AB=15m
Area of trapezium=1/2 AB(AD+BC)
=1/2×15(54+42)
=15×48
=720m sq.
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