The length of the fence of a trapezium shaped field ABCD is 130 meter and side AB is perpendicular to each of the parallel side AD and BC. If BC= 54 centimetres CD=19 meter and AD= 42 meter, find the area of the field. This solution of the question.
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so area of trapezium =1//2 x h x (a+b)
so perimeter of trapezium=a+b+c+d
so if a side is perpendicular,then that is the height of the trapezium+ab
so ab=19+54+42+ab=130
ab=-130-115
ab=15m
so now area of trapezium=1/2 x 15 (42+19)
area=1/2 x 915
=457.5 m square
hope it helped. please mark me as brainliest :):):):):):):):):):
udayraj768oy9yd5:
please ignore that +ab in third line!!it is =ab
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