Question

The length of the fence of a Trapezium shaped field pqrs is 120 M. if QR = 48 m ,RS = 70 m and PS = 40 m, find the area of the field side PQ is perpendicular to the parallel side PS and QR

Answer 1

Answer:

The area is 660 $m^{2}$.

Step-by-step explanation:

Let x be the lenght of PQ.

Then we have:

x + 40 + 48 + 17 = 120

x + 105 = 120

x = 120 - 105

x = 15

Now that we have all the sides measurements we can compute the area.

Let a and b be the parallel sides, 40 m and 48 m respectively.

The height, h, of the trapezium is PQ, that is 15.

Area of a trapezium:

$\frac{1}{2}(a + b)$ x h = $\frac{1}{2}(40 + 48) . 15$

= 44 x 15 = 660 $m^{2}$

Thus, the area is 660 $m^{2}$.