The length of the longest pole that can be put in a room of dimensions 10 m multiply 10 m multiply 5 m.
Please answer me along with the solution and explaination.
Answers
Answered by
1
As it is a cuboid the longest pole that could be put is in the Diagnol whose formula is √l²+b²+c²= √100+100+25 =15 m
hence the length of the longest pole that could be put is 15m
hence the length of the longest pole that could be put is 15m
Answered by
1
firstly you have to find out room's base diagonal
then you have to find out
the diagonal whose base will the diagonal that you have find out already
then you have to use Pythagorean triplet
h2=p2+b2
p=height of room
b=room base diagonal
given photo has simple formula is
then you have to find out
the diagonal whose base will the diagonal that you have find out already
then you have to use Pythagorean triplet
h2=p2+b2
p=height of room
b=room base diagonal
given photo has simple formula is
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