Question

The length of the longest pole that can be put in the room of dimensions 10m by 10m by 5m

Answer 1

Given:

• length, l = 10m
• breadth, b = 10m
• height, h = 5m

Since It is a cuboid ( length, breadth and height are different ).

We know that,

Longest side of a cuboid is given by the formula:

$\qquad \quad \; \boxed{D = \sqrt{l^2 + b^2 + h^2}}$

$\Rightarrow \qquad \sqrt{(10)^2 + (10)^2 + (5)^2 } \\ \Rightarrow \qquad \sqrt{100 + 100 + 25} \\ \Rightarrow \qquad \sqrt{225} \\ \\ \therefore D = 15$

ANSWER: 15 METERS

Answer 2

$\bold{\underline{\underline{\huge{\sf{ANSWER\::}}}}}$

Given:

The dimensions of a room;

• Length= 10m
• Breadth=10m
• Height= 5m

To find:

The length of the longest pole.

Explanation:

We know that formula of the diagonal of a cuboid:√l² + b² + h²

→ Diagonal of room= $\sqrt{(10)^{2} +(10)^{2} +(5)^{2} }$

→ Diagonal of room= $\sqrt{100+100+25}$

→ Diagonal of room= $\sqrt{225}$

→ Diagonal of room= 15m

Thus,

The length of the longest pole is 15m.