Question

The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes

Answer 1

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Length of minute hand = radius of the clock (circle)

∴ Radius (r) of the circle = 14 cm (given)

Angle swept by minute hand in 60 minutes = 360°

So, the angle swept by the minute hand in 5 minutes = 360° × 5/60 = 30°

We know,

Area of a sector = (θ/360°) × πr2

Now, area of the sector making an angle of 30° = (30°/360°) × πr2 cm2

= (1/12) × π142

= (49/3)×(22/7) cm2

= 154/3 cm2

Answer 2

Answer:

Area =51.33

Step-by-step explanation:

Length of clock will be radius of clock ,

Thus , radius = 14cm

We know that total no. of minutes in clock = 60 min

Thus angle between the each five minutes = 360⁰×5/60 =30⁰ ( Let us assume this angle as Ø)

Now we know that area of sector = Ø/360⁰×πr²

Thus ,

⇒Area swept by the minute hand in 5 minutes =30⁰/360⁰×22/7×14×14

⇒Area swept by the minute hand in 5 minutes

= 1/12×44×14

= 616/12

= 51.33 cm² (approx.)

Thus the area swept by the minute hand in 5 minutes = 51.33 cm²