The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.
Answers
Answer:
The angle described by the minute hand in 5 minutes is 51.33 cm².
Step-by-step explanation:
Given :
Radius of circle,r = 14 cm
Angle described by the minute hand in one minute = 6°
Angle described by the minute hand in 5 minutes ,θ = 6°× 5 = 30°
Angle swept by the minute hand in 5 minutes = Area of sector of angle 30° in a circle of radius 14 cm
Area of the sector of a circle, A = (θ/360) × πr²
A = (30°/360°) × π ×14²
A = 1/12 × 22/7 × 14 × 14
A = (22 × 14 × 14) /(12×7)
A = (11 × 2 × 7) /(6)
A = 154/3
A = 51.33 cm²
Angle described by the minute hand in 5 minutes , A = 51.33 cm²
Hence, the angle described by the minute hand in 5 minutes is 51.33 cm².
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the area swept by the 5 minutes 14×5=70cm