Math, asked by kru6th6ikaasrijz, 1 year ago

The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.

Answers

Answered by susi1
22
degree between2 numbers =360÷12=30
time between 2 numbers =5minutes
for 5 minutes 30degree angle
then for 10 minutes=60degree angle
area of sector=x÷360×πr2
=60÷360×22÷7×14×14
=308÷3
=102.66

susi1: I m sorry i did the area swept by minutes hand in 10 minutes. so in my solution u substitute 30 degree instead of 60 degrees
Answered by Anonymous
16

Length of minute hand = radius of the clock (circle)

∴ Radius (r) of the circle = 14 cm (given)

Angle swept by minute hand in 60 minutes = 360°

So, the angle swept by the minute hand in 5 minutes = 360° × 5/60 = 30°

We know,

Area of a sector = (θ/360°) × πr2

Now, area of the sector making an angle of 30° = (30°/360°) × πr2 cm2

= (1/12) × π142

= (49/3)×(22/7) cm2

= 154/3 cm2

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