the length of the minute hand of a clock is 4cm.find the area swept by the minute hand in 5minutes
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parveen36:
thanks sis
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HEYAAA.....
HERES YOUR ANS....
theta = 360/12
=> 30°
Now area swept will be
= πr² × theta/360
=> 22/7× 4 ×4 × 30/360
=> 4.18 cm2
HOPE THIS HELPS
HERES YOUR ANS....
theta = 360/12
=> 30°
Now area swept will be
= πr² × theta/360
=> 22/7× 4 ×4 × 30/360
=> 4.18 cm2
HOPE THIS HELPS
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