Question

The length of the minute hand of a clock is 5 cm .find the area swept by the minute hand during the time period 6:05 a.m. and 6:40 a.m.

Plzz answer it fast...
Maths sum:-):-)

Answer 1

Answer:40.34cm2

Step-by-step explanation:

Area of sector =185÷360×3.14×25. =40.34

Answer 2

As the minute hand is 5 cm in length

radius of the sector= 5 cm

Also minute hand is completing a semicircle during the time period 6:05 am to 6:40 am so central angle=180°

we know that

area of sector= central angle/360× 22/7×r^2

=180/360×22/7×5×5

=11×25/7

=39.28571

~39.29 sq.cm

the minute hand swept 39.29 sq cm area