The length of the minute hand of a clock is 6 cm. Find the area swept by the minute hand
during the time period 8:05 am and 8:45 am.
Answers
Answered by
13
r= 6cm
x= 360*40/60=240
area of a sector= πr²*x/360
=36π*240/360=36π*2/3=72π/3=24 π cm²
x= 360*40/60=240
area of a sector= πr²*x/360
=36π*240/360=36π*2/3=72π/3=24 π cm²
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Answered by
20
Here length of minute hand is given as 6cm
So its means radius = 6 cm
8:05 AM - 8:45 AM
= 40 Minutes
Ф = 6 × minutes
Ф = 6 × 40 = 240
Now area swept by minute hand = Ф/360 × πr²
240/360 × 22/7 ×(6)²
44/21 × 36
= 75.428 cm²
So its means radius = 6 cm
8:05 AM - 8:45 AM
= 40 Minutes
Ф = 6 × minutes
Ф = 6 × 40 = 240
Now area swept by minute hand = Ф/360 × πr²
240/360 × 22/7 ×(6)²
44/21 × 36
= 75.428 cm²
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