Question

The length of the minute hand on a wall clock is 7 cm. the area swept by the minute hand in 30 minutes is

Answer 1

Answer:

Imin=6*

30min=30x6

=180

So 180*

180/360x22/7x7x7

1/2x22x7

77cm^2

Thanks

Answer 2

Given

• length of the minute hand on a wall clock is 7 cm.
• in 30 minutes

To find

• area swept by the minute hand in 30 minutes is

solution

we are provided with the length of the minute hand of a clock and are required to find the area sweft by the minute hand in 30 minutes.

since the given questions arrangement make it a sector we are required to find the area of the sector.

the angle made by the minute hand of a clock by 30 minutes would be,

for travelling 1 minute the angle sept by the minute clock is 6 degree. Therefore, for travelling 30 minutes angle swept by the minute clock would be, 6× 30 = 180°

Thus, the area of the sector of angle 180 degree would be,

A = angle/ 360 (πr^2)

or, A = 180/360 (π 7^2)

or, A = 1/2 ( 22× 7)

or, A = 77 sq. cm

Therefore the area sweft by the minute hand of the clock will be 77sq. cm.