Question

the length of the pence of a traperium shaped feild is 130 m and side AB is perpendicular to each of the parllel side AD and BC if bc =54 m cd =19 m and ad 42 find the area of the field​

Answer 1

Length of fence=120m

120=AB+BC+CD+AD

120=AB+105

AB=120-105

=15m

Area of trapezium field=$\frac{1}{2} (sum \: of \: parlel \: sides) \times (distance \: between \: them) \\ = \frac{1}{2} \times( AD + BC) \times AB \\ = \frac{1}{2} \times (40 + 48) \times 15 \\ = \frac{1}{2} \times 88 \times 15 \\ = 660 \: {m}^{2}$