Question

the length of the rectangle double to the breadth of it the area of the rectangle is 159Sq units .then find the length &breadth of the rectangle ?​

Answer 1

Let

• Breadth=x
• Length=2x

AREA=1596SQ.UNITS

we know

$\boxed{\sf Area=Length\times Breadth}$

$\\ \sf\longmapsto x\times 2x=159$

$\\ \sf\longmapsto 2x^2=159$

$\\ \sf\longmapsto x^2=\dfrac{159}{2}$

$\\ \sf\longmapsto x^2=79.5$

$\\ \sf\longmapsto x=\sqrt{79.5}$

$\\ \sf\longmapsto x=8.3$

$\\ \sf\longmapsto 2x=2(8.3)=16.6$

• Length=16.6units
• Breadth=8.3units

Answer 2

$\mathfrak{Solution-:}$

Given-:

• Length of the Rectangle is double of its breadth.
• Area of the Rectangle = 159 sq.unit.

To Find-:

• Length of the Rectangle = ?
• Breadth of the Rectangle = ?

Using Formula-:

• Area of a Rectangle = Length × Breadth

Calculation-:

• Let the breadth of the Rectangle be x
• Then, its Length will be 2x

ACCORDING TO THE QUESTION

x × 2x = 159

2x² = 159

x² = $\frac{159}{2}$

x² = 79.5

x = $\sqrt{79.5}$

x = 8.3

• Breadth of the Rectangle = x = 8.3 units
• Length of the Rectangle = 2x = 2 × 8.3 = 16.6 units

$\rule{200pt}{4pt}$

MORE TO KNOW-:

★ Perimeter-: Perimeter of a closed figure is the sum of lengths of all the sides.

↦Rectangle

Perimeter of a Rectangle = 2 (Length + Breadth)

↦Square

Perimeter of a Square = 4 × Side

↦Equilateral Triangle

Perimeter of a Equilateral Triangle = 3 × Side of a Triangle

______________________________

★ Area-: Area of a closed figure is the amount of region or plane enclosed by it.

↦Rectangle

Area of a Rectangle = Length × Breadth

↦Square

Area of a Square = (Side)²

↦Irregular Figure-: Area of Irregular figures is calculated using following steps:

Step 1: Count full squares, half squares and more than half of squares covered by the figure separately.

Step 2: Area covered by a full square and more than half of a square is counted as 1 sq. unit.

Step 3: Area covered by half of a square is counted as 1/2 sq. unit.

Step 4: Portions that covers less than half of a square are ignored.