The length of the rectangle exceeds twice its breatj by 1 meter . if the area of the rectangle is 55 sq m . findd length abd breath
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let the breadth of rectangle(b) be x m
length of rectangle(l)=2x+1 m
now
area of the rectangle(a)=55 sq. m
or, l*b=55
or, (2x+1)*x=55
or, 2x^2+x-55=0
or, 2x^2+11x-10x-55=0
or, (2x+11)(x-5)=0
either,
2x+11=0
x==11/2(impossible)
or,
(x-5)=0
x=5 m
again,
length of the rectangle(l)=(2x+1)=2*5+1=11m
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