Question

the length of the rectangle is 20 cm and perimeter is 60 cm what is its breadth and area​

Answer 1

ANSWER :

Breadth of the rectangle is 10 cm and the area of the rectangle is 200 cm².

EXPLANATION :

GIVEN :-

• Length of rectangle = 20 cm.
• Perimeter of rectangle= 60 cm.

TO FIND :-

• Breadth and area of the rectangle.

SOLUTION :-

Let the breadth of the rectangle be x cm.

Perimeter = 60 cm.

Length = 20 cm.

We know,

★$\sf{Perimeter\:of\: rectangle=2(Length+Breadth)}$

So, Perimeter = 2(20+x) cm.

According to the question,

2(20+x)=60

→20+x = 60/2

→20+x = 30

→ x = 30 - 20

→ x = 10

Breadth = 10 cm.

Length = 20 cm.

★$\sf{Area\: of\: rectangle=length\times\: breadth}$

Area = (20 × 10 ) cm²

→Area = 200 cm²

Therefore, breadth of the rectangle is 10 cm and the area of the rectangle is 200 cm².

________________________

VERIFICATION :-

Length = 20 cm

Breadth = 10 cm

Perimeter = 2(20+10) cm

→ Perimeter= 60 cm

Hence Verified____!!

______________________

Answer 2

Step-by-step explanation:

Given -

• Length of the rectangle = 20 cm
• Perimeter of the rectangle = 60 cm

To find -

• Breadth of the rectangle
• Area of the rectangle

Now,

As we know that,

• Perimeter = 2(l + b)

here,

l = length

b = breadth

= 60 = 2(20 + b)

= 60/2 = 20 + b

= 30 = 20 + b

= 30 - 20 = b

• = b = 10 cm

Now,

As we know that,

• Area of rectangle = l × b

here,

l = length

b = breadth

= area = 20 × 10

• = area = 200 cm²

Hence,

The breadth of the rectangle is 10 cm

and

The area of the rectangle is 200 cm²

Verification -

Perimeter of rectangle = 2(l + b)

= 60 = 2(20 + 10)

= 60 = 2 × 30

= 60 = 60

LHS = RHS

Hence,

Verified..

Formula Used -

• Perimeter of rectangle = 2(l + b)
• Area of rectangle = l × b

Additional information -

• Each angle of rectangle is equal to 90°
• Opposite sides are equal.