the length of the rectangle is 27 longer than its breath if the perimeter of rectangle is 110m find its area
Answers
Answered by
3
let the breadth be x and then length will be x+27
perimeter of rectangle =2(l+b)
here, perimeter of rectangle =2(27+x+x)
110=2(27+2x)
110/2 =27+2x
55=27+2x
55-27=2x
28=2x
28/2=x
14=x
then breadth is 14 and length is (14+27)=41
area of rectangle is length*breadth
here, area of rectangle=14*41
area of rectangle =574m^2
i hope this will help
perimeter of rectangle =2(l+b)
here, perimeter of rectangle =2(27+x+x)
110=2(27+2x)
110/2 =27+2x
55=27+2x
55-27=2x
28=2x
28/2=x
14=x
then breadth is 14 and length is (14+27)=41
area of rectangle is length*breadth
here, area of rectangle=14*41
area of rectangle =574m^2
i hope this will help
Answered by
3
L = x + 27
B = x
The perimeter of the rectangle = 110
2(l + b) = 110
2(x + x + 27) = 110
2(2x +27) =110
4x + 54 = 110
4x = 110 - 54
4x = 56
x = 56/4
x = 14 m
L = x + 27 = 14 + 27 = 41 m
B = x = 14 m
The area of the rectangle
= l × b
= 14 × 41
= 574 m^2
B = x
The perimeter of the rectangle = 110
2(l + b) = 110
2(x + x + 27) = 110
2(2x +27) =110
4x + 54 = 110
4x = 110 - 54
4x = 56
x = 56/4
x = 14 m
L = x + 27 = 14 + 27 = 41 m
B = x = 14 m
The area of the rectangle
= l × b
= 14 × 41
= 574 m^2
achaldoshi23:
Please mark me as the brainliest answer
Similar questions