The length of the rectangle is 4 cm more than its breath it's diagonal is 4 cm more than the length find the length , breath and diagonal of rectangle
Answers
Step-by-step explanation:
hlo mate here's your answer
Correct option is
C9
Let breadth = x,
∴
L=
4+
x
Area=
(x)(4+x)=
45
4x+
x 2
45
x 2
4x−
45=
0
(x+9)(x−5)=
0
x=
5
x=
−9
not possible
∴
Length = x+4
= 5+4
= 9
i hope its help you mark as brainlist
Let the breadth of the rectangle be x cm.
Let the breadth of the rectangle be x cm.Then it's length = x+4 cm
Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)
Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)= 2(x+4+x) = 2(2x+4) = 4x + 8 cm
Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)= 2(x+4+x) = 2(2x+4) = 4x + 8 cmBut perimeter of the rectangle = 40 cm
Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)= 2(x+4+x) = 2(2x+4) = 4x + 8 cmBut perimeter of the rectangle = 40 cmSo. 4x + 8 = 40 => 4x = 40 - 8 => 4x = 32
Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)= 2(x+4+x) = 2(2x+4) = 4x + 8 cmBut perimeter of the rectangle = 40 cmSo. 4x + 8 = 40 => 4x = 40 - 8 => 4x = 32=> x = 32/4 => x = 8
Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)= 2(x+4+x) = 2(2x+4) = 4x + 8 cmBut perimeter of the rectangle = 40 cmSo. 4x + 8 = 40 => 4x = 40 - 8 => 4x = 32=> x = 32/4 => x = 8So breadth = 8 cmLength of the rectangle = x+4 = 8+4=12 cm