Math, asked by sonyshetty3110, 1 month ago

The length of the rectangle is 4 cm more than its breath it's diagonal is 4 cm more than the length find the length , breath and diagonal of rectangle​

Answers

Answered by ay8076191
0

Step-by-step explanation:

hlo mate here's your answer

Correct option is

C9

Let breadth = x,

L=

4+

x

Area=

(x)(4+x)=

45

4x+

x 2

45

x 2

4x−

45=

0

(x+9)(x−5)=

0

x=

5

x=

−9

not possible

Length = x+4

= 5+4

= 9

i hope its help you mark as brainlist

Answered by GιяℓуSσυℓ
0

Let the breadth of the rectangle be x cm.

Let the breadth of the rectangle be x cm.Then it's length = x+4 cm

Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)

Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)= 2(x+4+x) = 2(2x+4) = 4x + 8 cm

Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)= 2(x+4+x) = 2(2x+4) = 4x + 8 cmBut perimeter of the rectangle = 40 cm

Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)= 2(x+4+x) = 2(2x+4) = 4x + 8 cmBut perimeter of the rectangle = 40 cmSo. 4x + 8 = 40 => 4x = 40 - 8 => 4x = 32

Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)= 2(x+4+x) = 2(2x+4) = 4x + 8 cmBut perimeter of the rectangle = 40 cmSo. 4x + 8 = 40 => 4x = 40 - 8 => 4x = 32=> x = 32/4 => x = 8

Let the breadth of the rectangle be x cm.Then it's length = x+4 cmPerimeter of the rectangle= 2(l+b)= 2(x+4+x) = 2(2x+4) = 4x + 8 cmBut perimeter of the rectangle = 40 cmSo. 4x + 8 = 40 => 4x = 40 - 8 => 4x = 32=> x = 32/4 => x = 8So breadth = 8 cmLength of the rectangle = x+4 = 8+4=12 cm

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