Question

the length of the rectangle is 5 cm more than its breadth if the perimeter of the rectangle is 40 cm find the area of rectangle

Answer 1

Let the breadth be x cm
length=x+5 cm
perimeter =2 (l+b)=
2 (x+5+x)=4x+10 cm

4x+10=40
4x=30
x=30/4=7.5
so breadth=7.5 cm ; length=12.5 cm
area=l×b= 12.5×7.5=93.75
$so \: area \: = 93.75 {cm}^{2}$

Hope its helpful!!!

Answer 2

Answer: Area of rectangle = 93.75 cm²

Step-by-step explanation:

Given : The length of the rectangle is 5 cm more than its breadth in the question, and the perimeter of the rectangle is 40 cm

To Find : Find the area of  required rectangle

Solution :

Let the breadth of the rectangle be bb.

∴ Length of rectangle = (bb + 5 ) cm

It is given that the perimeter of the rectangle = 40 cm

We know that, perimeter of rectangle = 2 (length of rectangle + breadth of rectangle)

∴ Perimeter of the given rectangle = $2 (bb + 5 + bb)$  = 2 (2bb + 5)  = 4bb + 10

⇒ 40 = 4bb + 10

⇒ 30 = 4bb

∴ bb = 7.5 cm = Breadth of rectangle

∴ Length of rectangle = 7.5 + 5 = 12.5 cm

∴ Area of the required rectangle = length * breadth

                                                      = 12.5 * 7.5 = 93.75 cm²

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