The length of the rectangle is 5 cm more than its width and the area is 50 cm square find the length of the rectangle
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2
20 CM is the answer for the question
bgd:
can you give me solution
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10
hiii!!!
here's ur answer...
given that the length of the rectangle is 5 cm more than the breadth of thr it's width.
let the breadth (width) of the rectangle be x.
therefore length of the rectangle is x + 5
area of the rectangle = 50cm^2
==> l * b =50cm^2
==> ( x+5)5 = 50cm^2
==> 5x + 25 = 50cm^2
==> 5x = 50 - 25
==> 5x = 25
==> x = 25/5
==> x = 5cm
hence, breadth of the rectangle = x = 5cm
length of the rectangle = x + 5 = 5 + 5 = 10cm
hope this helps..!!
here's ur answer...
given that the length of the rectangle is 5 cm more than the breadth of thr it's width.
let the breadth (width) of the rectangle be x.
therefore length of the rectangle is x + 5
area of the rectangle = 50cm^2
==> l * b =50cm^2
==> ( x+5)5 = 50cm^2
==> 5x + 25 = 50cm^2
==> 5x = 50 - 25
==> 5x = 25
==> x = 25/5
==> x = 5cm
hence, breadth of the rectangle = x = 5cm
length of the rectangle = x + 5 = 5 + 5 = 10cm
hope this helps..!!
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