The length of the rectangle is 5 more than twice its breadth. The
perimeter of a rectangle is 52 cm then find the length of the rectangle.
Answers
Step-by-step explanation:
Let breadth of the rectangle is x
So, length = 2x +5
Perimeter = 52cm
2(l+b) = 52
l+b = 52/2 = 26
2x+5 +x = 26
3x = 21
x= 7
So, breadth of rectangle is 7 cm
Length = 2(7) +5 = 14+5 = 19 cm
Plz mark brainliest..
Answer:
- Length of the rectangle is 19 cm.
Step-by-step explanation:
Given that:
- Length of a rectangle is 5 more twice its breadth.
- Perimeter of the rectangle is 52 cm.
To Find:
- Length of the rectangle.
Concept:
Here, it is given that length of a rectangle is 5 more than twice the breadth and perimeter of the rectangle is 52 cm, and we have to find the length.
Process:
To do so, we will let the breadth be x and then length will be (2x + 5). After that, we can create an equation as Perimeter of rectangle = 2(L + B). After solving the equation for x, we can substitute the value of x to (2x + 5) to get the length.
Let us assume:
- Breadth of the rectangle is x.
Then,
- Length of the rectangle will be (2x + 5).
As we know that:
Perimeter of rectangle = 2(L + B)
Where,
- L stands for length.
- B stands for breadth.
Substituting the values:
52 cm = 2(2x + 5 + x)
Adding 2x and x,
52 = 2(3x + 5)
Opening the brackets,
52 = 6x + 10
Transposing 10 from RHS to LHS and changing its sign,
52 - 10 = 6x
Subtracting 10 from 52,
42 = 6x
Transposing 6 from RHS to LHS and changing its sign,
42/6 = x
Dividing 42 by 6,
7 = x
Hence, x = 7.
Therefore,
Length = (2x + 5) = (2 × 7) + 5 = 14 + 5 = 19 cm