the length of the rectangle is(6/5) ofthe breadth.it's perimeter is 132,then find the area
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Answered by
21
Let the width of rectangle be a
Length = 6a/5
Perimeter = 2 ( a + 6a/5)
=> 132 = 2 ( 11a / 5)
=> 66 = 11a / 5
=> a = 66 × 5 / 11
=> a = 6 × 5
=> a = 30
Width = 30 cm
Length = 6 × 30 /5 = 6 × 6 = 36 cm
Area = Length × Width
= 30 × 36
= 1080 cm^2
Length = 6a/5
Perimeter = 2 ( a + 6a/5)
=> 132 = 2 ( 11a / 5)
=> 66 = 11a / 5
=> a = 66 × 5 / 11
=> a = 6 × 5
=> a = 30
Width = 30 cm
Length = 6 × 30 /5 = 6 × 6 = 36 cm
Area = Length × Width
= 30 × 36
= 1080 cm^2
Answered by
15
Let say that breadth be x.
If breadth is x Then length would be 6/5x
Perimeter =2(length+breadth)
132 = 2 (6/5x+x)
66 = 11x/5
x= 66×5/11 = 30
breadth = 30
length = 30×6/5 = 36
Area = length × breadth
= 30×36 = 1080
So 1080 is area of rectangle
If breadth is x Then length would be 6/5x
Perimeter =2(length+breadth)
132 = 2 (6/5x+x)
66 = 11x/5
x= 66×5/11 = 30
breadth = 30
length = 30×6/5 = 36
Area = length × breadth
= 30×36 = 1080
So 1080 is area of rectangle
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