Question

The length of the rectangle is twice of its width. Th area is 50 square meter . Find its perimeter

Answer 1

Answer:

Gud night...!!

let the width of the rectangle be x m

then its length will be 2x m

area of rectangle = L X B

$50m = 2x \times x$

$50m = 2x {}^{2}$

$x {}^{2} = \frac{50}{2} = 25$

$x = \sqrt{5} \times 5$

$x = 5m$

Width=5m

Length=5x2=10m

Brainliest please...

Answer 2

Gud night...!!

let the width of the rectangle be x m

then its length will be 2x m

area of rectangle = L X B

50m = 2x \times x50m=2x×x

50m = 2x {}^{2}50m=2x

2

x {}^{2} = \frac{50}{2} = 25x

2

=

2

50

=25

x = \sqrt{5} \times 5x=

5

×5

x = 5mx=5m

Width=5m

Length=5x2=10m

Brainliest please...