the length of the rectangle plot is 5m less than twice its breadth find the dimensions of the plot if its perimeter is 50 m
Answers
Answered by
7
hyy...
let the breadth be x meter
then, a/q
=> length = ( 2x - 5 ) meter
=> perimeter of rectangle = 2 ( l + b )
=> 50 = 2 ( 2x -5 + x )
=> 50 = 2( 3x - 5)
=> 25 = 3x - 5
=> 3x = 30 m
=> x = 10m
hence, breadth = 10 m and length = (2x - 5) = (2×10-5 ) = 15 m ...answer
hope this helps ! :-)
let the breadth be x meter
then, a/q
=> length = ( 2x - 5 ) meter
=> perimeter of rectangle = 2 ( l + b )
=> 50 = 2 ( 2x -5 + x )
=> 50 = 2( 3x - 5)
=> 25 = 3x - 5
=> 3x = 30 m
=> x = 10m
hence, breadth = 10 m and length = (2x - 5) = (2×10-5 ) = 15 m ...answer
hope this helps ! :-)
kiranjeetkaur:
thanks it helpful to me
Answered by
1
Hello
Your answer,
Let breadth be x m
So,
length = (2x-5) m
Given :-
Perimeter of the rectangle = 50
Perimeter of rectangle = 2(length+breadth)
=> 50 = 2 (2x-5 + x)
=> 50 = 2 (3x - 5)
=> 50 = 6x - 10
=> 50+10 = 6x
=> 60 = 6x
=> 60/6 = x
=> 10 = x
So,
breadth = x = 10 m
length = (2x-5) = (2*10 - 5) = 15 m
Hope this will be helpful
Your answer,
Let breadth be x m
So,
length = (2x-5) m
Given :-
Perimeter of the rectangle = 50
Perimeter of rectangle = 2(length+breadth)
=> 50 = 2 (2x-5 + x)
=> 50 = 2 (3x - 5)
=> 50 = 6x - 10
=> 50+10 = 6x
=> 60 = 6x
=> 60/6 = x
=> 10 = x
So,
breadth = x = 10 m
length = (2x-5) = (2*10 - 5) = 15 m
Hope this will be helpful
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