the length of the rectanglel lot is 6 less than thrice its width if the area is 45 square cm. what is the length and width of the rectangle
Answers
Answer:-
Let the breadth of the rectangle be x units.
Given:
Length of the rectangle is 6 less than thrice the breadth.
⟶ Length = (3x - 6) units
Also,
Area of the rectangle = 45 unit²
We know that,
Area of a rectangle = length * breadth
⟶ 45 = (3x - 6) * (x)
⟶ 45 = 3x² - 6x
⟶ 0 = 3x² - 6x - 45
⟶ 0 = 3x² - 15x + 9x - 45
⟶ 0 = 3x(x - 5) + 9(x - 5)
⟶ 0 = (3x + 9)(x - 5)
★ 3x + 9 = 0
⟶ 3x = - 9
⟶ x = - 9/3
⟶ x = - 3
★ x - 5 = 0
⟶ x = 5
Breadth cannot be negative. so - 3 is neglected.
Therefore,
- Length of the rectangle = 3x - 6 = 3(5) - 6 = 9 units
- Breadth of the rectangle = x = 5 units.
Given : The length of the rectangle lot is 6 less than thrice its width if the area is 45 square cm.
To find : What is the length and width of the rectangle?
Using formula :
★ Area = Length × Breadth.
Calculations :
- Let length be "BL - 6".
- Let breadth be "B".
→ 45 = (3B - 6) × B
→ 45 = 3B² - 6B
→ 3B² - 6B - 45 = 0
→ 3B² - 15B + 9B - 45 = 0
→ 3B (B - 5) + 9(B - 5) = 0
→ 3B + 9 = 0, B - 5 = 0
→ 3B = -9/3, B = 5
The value of Length or Breadth can't be negative so let's take the Positive value.
→ L = 3(5) - 6
→ L = 15 - 6
→ L = 9 units
→ B = 5 units
Therefore, this is the required answer.