Question

The length of the segment joining (6,2) and (3,6)

Answer 1

Answer:

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Explanation:

$d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$

$d = distance</p><p>$

$(x_1, y_1) = coordinates of the first point \\ </p><p>(x_2, y_2) = coordinates of the second point</p><p>$

$d \: = \sqrt{ {(3 - 6)}^{2} + {(6 - 2)}^{2} } \\ = > d = \sqrt{9 + 16} \\ = > d \: = \sqrt{25} \\ = > d \: = 5$

Therefore, The length of the segment joining (6,2) and (3,6) is 5 units