Question

the length of the shadow of a tower is 153 m high is 45m at a particular time . find the height of the electric pole whose shadow is 20m long at the same time

pls answer this question don't use tan bcuz I am in 8th grade and I don't have tan pls​

Answer 1

Answer:

Given:

✰ The length of the shadow of a tower = 153 m

✰ Height of tower = 45 m

✰ Shadow of an electric pole = 20 m

To find:

✠ The height of an electric pole.

Solution:

Here in this question first make and visual the diagrams as provided in attachment. Have look at the diagrams and there we will find the value of DE and we know to find DE we will use tan θ , first find out tan θ in first case of tower and then substitute the value of tan θ in second case of electric pole to find out DE i.e, the height of an electric pole.

In ∆ABC

⟹ tan θ = AB/BC

⟹ tan θ = 153/45 ...①

In ∆DEF

⟹ tan θ = DE/EF

⟹ tan θ = DE/20 ...②

Substitute the value of eq① in eq②

⟹ 153/45 = DE/20

By cross multiplication method,

⟹ DE = (153 × 20)/45

⟹ DE = 3060/45

⟹ DE = 68 m

∴ The height of an electric pole = 68 m

Step-by-step explanation:

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