Question

the length of the shadow of a tower is 153 metres high is 45 metres at a particular time. Find the height of an electric pole whose shadow is 20 metres long at the same time​

Answer 1

Answer:

153/45= x/20

x=153×20/45

Step-by-step explanation:

X= 68 metres

Answer 2

Let x be height of the pole .

then ,

$\sf \frac{153}{45} = \frac{x}{20} \implies \frac{17}{5} = \frac{x}{20} \implies \frac{17 \times 20}{5} = x$

$\sf x = 17 \times 4 = 68 \: \: meters$

∴ Height of the Electric Pole = 68 meters

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