Question

The length of the side of a triangle are 13 cm and 13 cm and 10 cm find its area also find the length of altitude from the opposite vertex to the side whose length is 10 centimetre​

Answer 1

Answer:

Let

A= 13cm

B= 13cm

C= 10cm

Now, perimeter of the triangle= (13+13+10)cm

=> perimeter of the triangle= 36cm

Therefore, semi perimeter of the triangle= 36/2 cm

=> s= 18 cm

Now, by HERON'S FORMULA,

ar(triangle)= √[s(s-A)(s-B)(s-C)]

=>ar(triangle)= √[18(18-13)(18-13)(18-10)]

=>ar(triangle)= √[18×5×5×8 × cm⁴]

=>ar(triangle)= √3600cm⁴

=>ar(triangle)= 60cm²----(a)

Now, let the altitude on side C= 10cm be "X"

ar(triangle)= 1/2 × 10cm × X { taking the side with 10cm as base }

=> 60cm²= 5Xcm {from (a)}

=>X= (60cm²)/(5cm)

=>X= 12cm

THEREFORE X= 12cm (WHICH IS THE REQUIRED ALTITUDE)

AND THE AREA OF THE TRAINGLE IS *60CM²*!!!

Step-by-step explanation:

Answer 2

Answer:

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