Question

the length of the side of an equilateral triangle is Sin 60 degrees units then find the area of the triangle​

Answer 1

Answer:

0.324

Step-by-step explanation:

first, all side of triangle is equal Sin60degree=0.866 then

Tan60degree is equal x / 0.433  , x = 0.749

area of half triangle is  1/2 * 0.866 * 0.749 =  0.324

Answer 2

Area of triangle is 0.324 sq. cm.

Step-by-step explanation:

Since we have given that

Length of side of an equilateral triangle = $\sin 60^\circ$

Since we know that

$\sin 60^\circ=\dfrac{\sqrt{3}}{2}$

So, Area of equilateral triangle would be

$\dfrac{\sqrt{3}}{4}\times side^2\\\\=\dfrac{\sqrt{3}}{4}\times \dfrac{\sqrt{3}}{2}\times \dfrac{\sqrt{3}}{2}\\\\=\dfrac{3\sqrt{3}}{16}\\\\=0.324\ cm^2$

Hence, area of triangle is 0.324 sq. cm.

# learn more:

If in an equilateral triangle the length of the median is root3cm then find the length of the side of the equilateral triangle.

https://brainly.in/question/1841126