The length of the sides of a triangle are in the ratio of 5:12:13 and its
perimeter is 90 m find the area of the triangle
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given ratio of sides of the triangle = 5:12:13
let the constant ratio be ' x'
so now sides are , 5x , 12x , 13x
given perimeter(sum of all sides)= 90 m
5x + 12x + 13x = 90
30x = 90
x = 3
now length of sides are 5x= 5×3 = 15 m
12x = 12×3 = 36 m
and
13x = 13×3 = 39 m
since , we know( 15,36,39 ) is a triplet of right angled triangle.
so now , base = 15 ,h = 36
area of triangle = 1/2 × base × height
=1/2 × 15 × 36
=15 × 18 = 270m^2
therefore the required area of triangle=270m^2
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Your Answer : area = 270 m^2
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let the constant ratio be ' x'
so now sides are , 5x , 12x , 13x
given perimeter(sum of all sides)= 90 m
5x + 12x + 13x = 90
30x = 90
x = 3
now length of sides are 5x= 5×3 = 15 m
12x = 12×3 = 36 m
and
13x = 13×3 = 39 m
since , we know( 15,36,39 ) is a triplet of right angled triangle.
so now , base = 15 ,h = 36
area of triangle = 1/2 × base × height
=1/2 × 15 × 36
=15 × 18 = 270m^2
therefore the required area of triangle=270m^2
________________________________
Your Answer : area = 270 m^2
________________________________
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