The length of the solid diagonal of a cuboid is D units and the sum of the lengths of all its edges is A units then find its total surface area
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length of solid diagonal of cuboid = D
sum of all sides = A
let L, B , H are length , width and height of cuboid respectively
we know,
diagonal of cuboid = √(L² + B² + H²)
D = √( L² + B² + H² )
take square both sides
D² = L² + B² + H²
we know, according to algebraic identity, (a + b+ c)²= a² + b² + c² +2(ab +bc+ ca)
use this ,
(L + B + H )² = L² + B² + H² +2(LB +BH +HL)
(A)² = D² +{2(LB +BH + HL)}
surface area of cuboid =2(LB +BH + HL) =A² -D²
sum of all sides = A
let L, B , H are length , width and height of cuboid respectively
we know,
diagonal of cuboid = √(L² + B² + H²)
D = √( L² + B² + H² )
take square both sides
D² = L² + B² + H²
we know, according to algebraic identity, (a + b+ c)²= a² + b² + c² +2(ab +bc+ ca)
use this ,
(L + B + H )² = L² + B² + H² +2(LB +BH +HL)
(A)² = D² +{2(LB +BH + HL)}
surface area of cuboid =2(LB +BH + HL) =A² -D²
mysticd:
Excellent
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