the length of the tangents to a circle with radius 5 cm from a point which is 13 cm from the centre of the circle
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Answered by
2
Let the tangent be BC
Radius be AB
And the point from centre be AC
AB^2 + BC^2 = AC^2
5^2 + BC^2 = 13^2
25 + BC^2 = 169
BC^2 = 169 - 25
BC^2 = 144
BC = ROOT 144
BC = 12 cm
So the length of the tangent is 12cm.
Hope it helps you.
Radius be AB
And the point from centre be AC
AB^2 + BC^2 = AC^2
5^2 + BC^2 = 13^2
25 + BC^2 = 169
BC^2 = 169 - 25
BC^2 = 144
BC = ROOT 144
BC = 12 cm
So the length of the tangent is 12cm.
Hope it helps you.
musharraf111:
figure mein please
Answered by
5
Hiii friend,
Let PA a tangent and P be a point from the center of the circle.
OP (H) = 13 cm
Radius OA (P) = 5 cm
By pythagoras theroem,
(H) = (B)² + (P)²
(OP)² = (PA)² + (OA)²
(PA)² = (OP)² - (OA)²
(PA)² = (13)² - (5)² => 169 - 25 => 144
PA = ✓144 = 12 cm
Therefore,
Length of tangent PA = 12 cm
HOPE IT WILL HELP YOU.... :-)
Let PA a tangent and P be a point from the center of the circle.
OP (H) = 13 cm
Radius OA (P) = 5 cm
By pythagoras theroem,
(H) = (B)² + (P)²
(OP)² = (PA)² + (OA)²
(PA)² = (OP)² - (OA)²
(PA)² = (13)² - (5)² => 169 - 25 => 144
PA = ✓144 = 12 cm
Therefore,
Length of tangent PA = 12 cm
HOPE IT WILL HELP YOU.... :-)
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