The length of the two arms of the leader in a hydraulic place is 20 cm and 100 cm The radii of the upper and sixth pistons are 30 cm and 3 cm respectively What is the force applied to the piston when a ball of 196 N is applied to the handle of the lever?
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Explanation:
As in hydraulic press, pressure will be equally transferred
⇒P
1
=P
2
⇒
A
1
50×g
=
A
2
m×g
⇒
(1.25)
2
×π
50×10
=
(15)
2
×π
m×10
⇒m=7200kg
So, 7200kg weight should be put on a larger piston.
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