The length of two perpendicular chord AB and AC of a circle are 5 cm and 12 cm .find the radius of the circle
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AB=4 cm and AC=3 cm are two perpendicular cords of a circle. Angle A=90°,then BC wil be the diameter of circle,BC=2r.
In right angled triangle BAC
BC^2=AB^2+AC^2
(2r)^2=(4)^2+(3)^3
4r^2=16+9=25
r^2=25/4
r = 5/2 cm. or 2.5 cm , Answer
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