the length of two side of a right angle triangle are 6cm and 8cm. find the length of its hypotenuse
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Answered by
2
h square = 36 +64
h =100 root
h=10
h =100 root
h=10
Answered by
4
length of first side perpendicular ,p is 6cm
length of second side base ,b is 8 cm
so,
by Pythagoras therom ,

h^2=8^2+6^2
h^2=64+36
h^2=100
h^2=10^2
h = 10
hence the hypotenuse of the right angled triangle ,h is 10 cm
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length of second side base ,b is 8 cm
so,
by Pythagoras therom ,
h^2=8^2+6^2
h^2=64+36
h^2=100
h^2=10^2
h = 10
hence the hypotenuse of the right angled triangle ,h is 10 cm
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