the length of two sides of a triangle are 18 cm and 15 CM between what two measures should the of the third side fall
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Answer:
The length of the 3rd side of the wall is 30 cm.
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Answer:
Let AB,BC and CA are the sides of triangle ABC
Given that,
Let AB=15cm,BC=12cm and Third side CA=?
Then, We know that
CA=AB−BC
CA=15−12
CA=3cm.
And
CA=AB+BC
CA=15+12
CA=27cm.
So the third side CA must lie between 3<CA<27cm.
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