Math, asked by vishal2544, 11 months ago

find the value of cos(cos^-1x + cos^-1y) + cos(sin^-1x + sin^-1y)

Answers

Answered by HariesRam
5

Answer:

We know that

If cos^-1x + cos^-1y = 2pi

then sin^-1x + sin^-1y = -pi

By substituting the known values, we get

cos(cos^-1x + cos^-1y) + cos(sin^-1x + sin^-1y) =cos(2pi) + cos(-pi)

=1 + (-1)

=0

The value of

cos(cos^-1x + cos^-1y) + sin(sin^-1x + sin^-1y) = 0.

Hopes it helps you❤️

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Answered by Anonymous
11

Answer:

Please refer to the above attachment

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