find the value of cos(cos^-1x + cos^-1y) + cos(sin^-1x + sin^-1y)
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Answered by
5
Answer:
We know that
If cos^-1x + cos^-1y = 2pi
then sin^-1x + sin^-1y = -pi
By substituting the known values, we get
cos(cos^-1x + cos^-1y) + cos(sin^-1x + sin^-1y) =cos(2pi) + cos(-pi)
=1 + (-1)
=0
The value of
cos(cos^-1x + cos^-1y) + sin(sin^-1x + sin^-1y) = 0.
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11
Answer:
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