the length of two sides of an isosceles triangle are 8 centimetre and 14 centimetre the perimeter of the triangle in centimetres
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perimeter of ∆ = sum of all sides
14= 8+8+?
14=16+?
?=14-16
?=-2
then third side is equal to -2
and that's not possible so this ∆ is impossible
14= 8+8+?
14=16+?
?=14-16
?=-2
then third side is equal to -2
and that's not possible so this ∆ is impossible
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