Question

The length of wire required to make the network shown in the figure is 20 cm. Find the value of p and then the total area of the network. (a) 10 sq cm (b) 8 sq cm (c) 6 sq cm (d) 16 sq cm. length = (p+1)cm . breath = (p-1)cm​

Answer 1

Answer:

This is a Wheatstone bridge circuit. here four arms resistances , P=4Ω,Q=2Ω,R=6Ω,S=3Ω

since,

Q

P

=

S

R

so it is in balanced condition and no current flow the middle resistance 4Ω. Thus, it is removed from circuit.

Now equivalent resistance of the circuit is R

eq

=(4+2)∣∣(6+3)=6∣∣9=

6+9

6×9

=54/15=18/5Ω

Current, i=V/R

eq

=5V/18